javascript - Regex catch string between two strings, multiple lines - Stack Overflow

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I´m working on a *.po file, I´m trying to catch all the text between msgid "" and msgstr "", not really lucky, never more than one line:

msgid ""
"%s asdfgh asdsfgf asdfg %s even if you "
"asdfgdh sentences with no sense. We are not asking  translate "
"Shakespeare's %s Hamlet %s !. %s testing regex %s "
"don't require specific industry knowledge. enjoying "
msgstr ""

What I´ve tried:

var myArray = fileContent.match(/msgid ([""'])(?:(?=(\\?))\2.)*?\1/g);

Thanks for your help, I´m not really good with regex :(

I´m working on a *.po file, I´m trying to catch all the text between msgid "" and msgstr "", not really lucky, never more than one line:

msgid ""
"%s asdfgh asdsfgf asdfg %s even if you "
"asdfgdh sentences with no sense. We are not asking  translate "
"Shakespeare's %s Hamlet %s !. %s testing regex %s "
"don't require specific industry knowledge. enjoying "
msgstr ""

What I´ve tried:

var myArray = fileContent.match(/msgid ([""'])(?:(?=(\\?))\2.)*?\1/g);

Thanks for your help, I´m not really good with regex :(

• javascript
• regex

Share Improve this question Follow edited May 31, 2013 at 16:24 Jerry 71.6k1414 gold badges104104 silver badges146146 bronze badges asked May 31, 2013 at 16:22 lfergonlfergon 97311 gold badge1515 silver badges2727 bronze badges 0

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4 Answers 4

Sorted by: Reset to default 10

Here is one way to extract all of that text:

var match = text.replace(/msgid ""([\s\S]*?)msgstr ""/, "$1");

Example: http://jsfiddle/bqk79/

The [\s\S] is a character class that will match any character including line breaks, so [\s\S]*? will match any number of any character. In other languages you could use the s or DOTALL flag to make . match line breaks, but Javascript does not support this.

Note that you regex doesn't make any mention of single quotes, but if you need to be able to match between msgid '' and msgstr '' as well you can use the following:

var match = text.replace(/msgid (['"]{2})([\s\S]*?)msgstr \1/, "$2");

Try with this pattern:

/msgid (["']{2})\n([\s\S]*?)\nmsgstr \1/

The result is in the second capturing group, but you can make more simple with:

/msgid ["']{2}\n([\s\S]*?)\nmsgstr /

in the first capturing group

I realize that the question specifically asks for a regular expression, but you should consider using string split instead if you can.

Here is a ready-made function:

function extractTextBetween(subject, start, end) {
    try{
        return subject.split(start)[1].split(end)[0];
    } catch(e){
        console.log("Exception when extracting text", e);
    }
}

http://jsfiddle/b33hdh9b/3/

You could perhaps try this regex?

msgid ""((?:.|[\n\r])+)msgstr ""

((?:.|[\n\r])+) this is your catching group;

(?:.|[\n\r])+ This enables the match of . or [\n\r] multiple times, the \n\r are for newlines and carriage returns.

Tested

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