Javascript: Passing variable to function breaks function - Stack Overflow

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I am using an onsubmit variable to ensure that the user really means to delete something, however as soon as I put a value in the parenthesis inside the onsubmit it no longer calls the confirm box.

Code:

onClick="confirmSubmit(abc)"

Doesn't work but the following:

onClick="confirmSubmit()"

Does work

Function:

    function confirmSubmit(category)
{
var category = category;
var agree=confirm("Are you sure you wish to DELETE" + category + " and all of its subcategories and photos?");
if (agree)
    return true ;
else
    return false ;
}

I am using an onsubmit variable to ensure that the user really means to delete something, however as soon as I put a value in the parenthesis inside the onsubmit it no longer calls the confirm box.

Code:

onClick="confirmSubmit(abc)"

Doesn't work but the following:

onClick="confirmSubmit()"

Does work

Function:

    function confirmSubmit(category)
{
var category = category;
var agree=confirm("Are you sure you wish to DELETE" + category + " and all of its subcategories and photos?");
if (agree)
    return true ;
else
    return false ;
}

• javascript

Share Improve this question Follow asked Jul 20, 2011 at 18:55 George ReithGeorge Reith 13.5k1818 gold badges8282 silver badges151151 bronze badges 1

• confirm() returns a boolean, so you can shorten your return statement by just returning the return value of the confirm. return confirm("Are you sure...");. – user113716 Commented Jul 20, 2011 at 19:00

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4 Answers 4

Sorted by: Reset to default 5

you need quotes around your abc:

onclick="confirmSubmit('abc')"

Without them you are trying to pass a variable, abc, which doesn't exist and triggers an error

onClick="confirmSubmit(abc)" is trying to pass the variable abc, if you intend to pass a string with the value "abc" then do this:

onClick="confirmSubmit('abc')"

function confirmSubmit(category)  
{  var category = category;  

And you've declared "category" twice! Once in the function header and then as a function variable in the next line! What for?

You're try to pass the variable abc (which does not exist) to the function. Do: onclick="return confirmSubmit('abc');"

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