javascript - JOI how to allow empty spaces and punctuation - Stack Overflow

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I want to allow Joi to allow spaces/whitespaces in a title field of a form.

Working tomorrow with Jude.

should be allowed as wel as

Morningwalk

At this moment only the last one is validated as true. Here is my joi validation:

const schema = Joi.object().keys({
  title: Joi.string().alphanum().required().max(50),

I want to allow Joi to allow spaces/whitespaces in a title field of a form.

Working tomorrow with Jude.

should be allowed as wel as

Morningwalk

At this moment only the last one is validated as true. Here is my joi validation:

const schema = Joi.object().keys({
  title: Joi.string().alphanum().required().max(50),

I added Regex but without result.

title: Joi.string().alphanum().required().max(50), regex(
  new RegExp('^\w+( +\w+)*$'))

What is the right way?

• javascript
• node.js
• regex
• vue.js
• joi

Share Improve this question Follow edited Mar 18, 2019 at 13:46 Tichel asked Mar 18, 2019 at 13:23 TichelTichel 53122 gold badges1212 silver badges2626 bronze badges 6

• 1 What if you replace new RegExp('^\w+( +\w+)*$') with /^\w+( +\w+)*$/? – Wiktor Stribiżew Commented Mar 18, 2019 at 13:24
• still not allow spaces – Tichel Commented Mar 18, 2019 at 13:28
• 1 Probably, you need to remove .alphanum() – Wiktor Stribiżew Commented Mar 18, 2019 at 13:29
• Works. Now only add punctuation marks to regex. cheers – Tichel Commented Mar 18, 2019 at 13:33
• So, you mean /^\w+(?:\W+\w+)*$/? – Wiktor Stribiżew Commented Mar 18, 2019 at 13:34

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1 Answer 1

Sorted by: Reset to default 3

The .alphanum() makes your check ignore whitespace. Also, when you define a regex using a constructor notation, you are using a string literal where backslashes are used to form string escape sequences and thus need doubling to form regex escape sequences. However, a regex literal notation is more convenient. Rather than writing new RegExp('\\d') you'd write /\d/.

So, you may use this to allow just whitespaces:

title: Joi.string().required().max(50), regex(/^\w+(?:\s+\w+)*$/)

However, you seem to want to not allow mas and allow all other punctuation.

Use

title: Joi.string().required().max(50), regex(/^\s*\w+(?:[^\w,]+\w+)*[^,\w]*$/)

Details

• ^ - start of string
• \s* - 0 or more whitespaces (or, use [^,\w]* to match 0 or more chars other than ma and word chars)
• \w+ - 1 or more word chars (letters, digits or _, if you do not want _, replace with [^\W_])
• (?:[^\w,]+\w+)* - zero or more repetitions of
  • [^\w,]+ - 1 or more chars other than ma and word chars
  • \w+ - 1 or more word chars
• [^,\w]* - 0 or more chars other than ma and word chars
• $ - end of string.

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