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I have two toggles with a class .submenu-toggle and they contain a ul child with a class .submenu. What I would like to happen is when the user clicks on .submenu-toggle the ul child(.submenu) of that class(submenu-toggle) is shown and then when it is clicked again it is hidden.

I need to achieve this using pure Javascript without any JQuery.

If you're able to also let me know how to hide .submenu if the user clicks outside that element... that would be awesome!

Thanks for your time and help.

Here is my current Javascript:

      // Drop Down Menus
      var subToggle = document.getElementsByClassName("submenu-toggle");
      var menu = subToggle.children;

      for (var i = 0; i < subToggle.length; i++) {
          subToggle.item(i).onclick = function () {

              menu[1].style.display = "block";
          }
      }

Here is my current html:

<ul>
     <li class="submenu-toggle"><a href="#">Menu 1</a>
        <ul class="submenu">
            <li></li>
            <li></li>
            <li></li>
            <li></li>
            <li></li>
        </ul>
    </li>
    <li class="submenu-toggle"><a href="#">Menu 2</a>
        <ul class="submenu">
            <li></li>
            <li></li>
            <li></li>
            <li></li>
            <li></li>
        </ul>
    </li>
</ul>

I have two toggles with a class .submenu-toggle and they contain a ul child with a class .submenu. What I would like to happen is when the user clicks on .submenu-toggle the ul child(.submenu) of that class(submenu-toggle) is shown and then when it is clicked again it is hidden.

I need to achieve this using pure Javascript without any JQuery.

If you're able to also let me know how to hide .submenu if the user clicks outside that element... that would be awesome!

Thanks for your time and help.

Here is my current Javascript:

      // Drop Down Menus
      var subToggle = document.getElementsByClassName("submenu-toggle");
      var menu = subToggle.children;

      for (var i = 0; i < subToggle.length; i++) {
          subToggle.item(i).onclick = function () {

              menu[1].style.display = "block";
          }
      }

Here is my current html:

<ul>
     <li class="submenu-toggle"><a href="#">Menu 1</a>
        <ul class="submenu">
            <li></li>
            <li></li>
            <li></li>
            <li></li>
            <li></li>
        </ul>
    </li>
    <li class="submenu-toggle"><a href="#">Menu 2</a>
        <ul class="submenu">
            <li></li>
            <li></li>
            <li></li>
            <li></li>
            <li></li>
        </ul>
    </li>
</ul>

• javascript
• html

Share Improve this question Follow asked Nov 8, 2016 at 12:34 DBoiDBoi 68722 gold badges2020 silver badges3636 bronze badges 0

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1 Answer 1

Sorted by: Reset to default 5

You could easily do this menu with CSS. But here's an example with vanilla JavaScript:

// JS
var submenu = document.getElementsByClassName("submenu-toggle");

for (var i = 0; i < submenu.length; i++) {
    submenu[i].addEventListener('click', menus, false);
}

function menus() {
  var menu = this.querySelector('.submenu');
  menu.classList.toggle("hidden");
};

// CSS

.hidden {
   display: none;
}

DEMO - Codepen

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